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Tangential Velocity

  1. Dec 11, 2008 #1
    Suppose a 0.45kg ball is attached to a 1.00m long string. the force keeping the ball oving in a circular path is 45 N. What will the ball's centripetal acceleration and tangential velocity be?

    I got the first part, but I'm not sure how to get the 2nd part.

    So, I'm using v=r*omega. To find omega, I want to use F=mr*omega^2. Will that work?
  2. jcsd
  3. Dec 12, 2008 #2


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    Will you show the calculations in numbers?
  4. Dec 12, 2008 #3


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    Probably. BTW, the bold face is hard to read.
  5. Dec 12, 2008 #4
    The force keeping the ball in circular path is the centripetal force. Since f=ma, and we know that "a" must be the centripetal acceleration. What is centripetal acceleration equal to (you already found this, from there you should realize the a_cent is also equal to something else).
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