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Tattoo teaser

  1. Feb 9, 2006 #1
    Ok, I know this is not too much of a teaser but maybe you guys could come up with something cool and original. I'm getting a tattoo and part of it has my birthdate in it. Except I don't want it to be obvious...I want some type of complicated equation with lots of mathmatical symbols etc so if someone actually worked it out the solution would be my birthdate in international time format 75-05-12 or just 750512 as the answer. Any other suggestions are welcome. The winner will have the satisfaction of knowing their art is permanently on my body:biggrin:
     
  2. jcsd
  3. Feb 10, 2006 #2

    DaveC426913

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    Some one else asked about this a few months back. Their idea was to diagram the positions of the planets at the moment of their birth. I drew a graphic that represented it. I'll see if I can find it.

    If that interests you, I could probably whip up the graphic using your birthdate.

    Ah yes - here it is.
     
    Last edited: Feb 10, 2006
  4. Feb 13, 2006 #3

    DaveC426913

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    What time of day?
     
  5. Feb 13, 2006 #4

    DaveC426913

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    BTW, that's May 12 right? not Dec 5?
     
  6. Feb 13, 2006 #5
    Yeah, May 12 1975.
     
  7. Feb 14, 2006 #6

    DaveC426913

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    Here it is.
     

    Attached Files:

  8. Feb 14, 2006 #7
    not as simple as i'd like, but here's one with regular polygons -
    a triangle and 5 pentagons inscribed in a dodecagon...
    the 75 comes from 5 (only 1 shown here) x 5 sided figure x 3 (triangle)
    5 from the pentagon
    12 from the dodecagon. Best I got right now:blushing:
    It'd look something like this, but with an actual 12 sided polygon (this one is 15 sided)
     

    Attached Files:

    Last edited: Feb 15, 2006
  9. Feb 15, 2006 #8
    [tex]750512=\frac{\int_0^{\infty}{t^{10}e^{-t}dt}}{\pi(11)}+10^4\left(\sum_{k=1}^{4}{\frac{6k}{5^k}}+\frac{383}{625}\right)[/tex]

    ...I believe. Someone ought to check that.

    EDIT: Or also this...

    [tex]750512=\frac{\int_0^{\infty}{t^{10}e^{-t}dt}}{\pi(11)}+\frac{\pi^2\int_0^1{\left(\ln{\frac{1}{t}}\right)^8dt}}{12\zeta(2)}+2^4*7*41[/tex]
     
    Last edited: Feb 15, 2006
  10. Mar 2, 2006 #9
    That's great guys! For some reason it won't let me see the gifs though...it says I don't have permission to access those pages.
     
  11. Mar 2, 2006 #10
    You will have to log out, view the gifs, then log back in, it is a bug here at pf.
     
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