Hi I wonder if there is a simpler way to obtain the first three non-zero terms of Taylor Expansion for the function [tex]\frac{Ln(1+x)}{1-x}[/tex] about x=0?(adsbygoogle = window.adsbygoogle || []).push({});

I differentiated it directly, but it was such a nightmare to do . So I am wondering if there is a simpler way to do it?

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Taylor Expansion

Loading...

Similar Threads - Taylor Expansion | Date |
---|---|

I Which x_0 to use in a Taylor series expansion? | Feb 19, 2018 |

A I need some help with the derivation of fourth order Runge Kutta | Jan 27, 2017 |

I The a in Taylor series | Jul 22, 2016 |

I Expansion of ## e^{f(x)} ## | May 10, 2016 |

Taylor expansion | Dec 20, 2015 |

**Physics Forums - The Fusion of Science and Community**