# Taylor expansion

1. Apr 5, 2012

### Niles

1. The problem statement, all variables and given/known data
Hi

Say I want to Taylor-expand
$$f(\omega + m\sin(\Omega t))$$
where ω and Ω are frequencies, m is some constant and t denotes time. Then I would get
$$f(\omega + m\sin(\Omega t)) = f(\omega) + (m\sin(\Omega t)\frac{dI}{d\omega} + \ldots$$
Is it necessary to make any assumptions on the sizes of m and Ω in order to make the above expansion?

Best,
Niles.

2. Apr 5, 2012

### Dick

If you are Taylor expanding in the quantity you are adding to ω and I means f(ω) that's fine. If you are going to truncate the expansion there and wondering if it's a accurate expansion that's going to depend on the size of the quantity you are adding to ω and the behaviour of f''(ω). You'll want to look at Taylor series remainder terms if you are concerned about how good it is.

3. Apr 6, 2012

### Niles

Thanks!

Best,
Niles.

4. Apr 15, 2012

### Niles

5. Apr 15, 2012

### Dick

Sure it is. It's 'around' ω. I say the expansion is 'in' msin(Ωt) because that's the thing that appears in all the powers. Just terminology.

6. Apr 15, 2012

### Niles

Ah, I see. Thanks for clarifying.

Best,
Niles.