Taylor Polynomial Homework: Evaluate f^30(3)

In summary, the homework statement is that the Taylor polynomial of degree 100 for the function f about x=3 is given by p(x)= (x-3)^2 - (x-3)^4/2! +... + (-1)^n+1 [(x-3)^n2]/n! +... - (x-3)^100/50! with the value of f^30 (3) being 1/15! or 30!/15!
  • #1
yeahyeah<3
27
0

Homework Statement


The Taylor polynomial of degree 100 for the function f about x=3 is given by
p(x)= (x-3)^2 - (x-3)^4/2! +... + (-1)^n+1 [(x-3)^n2]/n! +... - (x-3)^100/50!
What is the value of f^30 (3)?

D) 1/15! or E)30!/15!


Homework Equations





The Attempt at a Solution


I know the bottom of the answer is 15! because n=15 (for the exponent to be 30) but I'm not sure what the top does.
 
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  • #2
By (-1)^n+1 [(x-3)^n2]/n!, do you mean:

[tex]\frac{(-1)^{n+1}}{n!}(x-3)^{2n}[/tex]

In any case, ask yourself this: What does the term with [itex]f^{(30)}(3)[/itex] in the Taylor expansion look like?
 
  • #3
how do you get the math problem to look like that -.-

and that is the question I'm asking for help on...

i think the term looks like
(x-3)^30
15!
?

but how does that answer the question?
Thanks!
 
  • #4
yeahyeah<3 said:
how do you get the math problem to look like that -.-
See here.

i think the term looks like
(x-3)^30
15!
?
That's what it looks like in p(x), but if you didn't know of p(x), what would the term look like?
 
  • #5
I'm not sure what you mean..?

like f'(30) (x-3)^30 kind of thing?
30!
 
  • #6
yeahyeah<3 said:
like f'(30) (x-3)^30 kind of thing?
30!
Yes, that kind of thing. So now you know what the general form of the term looks like and what it actually is. I leave the rest to you.
 
  • #7
i still don't understand =/I know the bottom of the term is 15! but I don't know how to get what the top is...
 
  • #8
You wrote, sort of, that the term that contains [itex]f^{(30)}(3)[/itex] is

[tex]\frac{f^{(30)}(3)}{30!}(x-3)^{30}[/tex]

and this should equal

[tex]\frac{(x-3)^{30}}{15!}[/tex]

right? So what is [itex]f^{(30)}(3)[/itex]?
 
  • #9
so it is E 30!
15!
Thanks so much!

just one last question..
I don't understand how you got
[tex]
\frac{f^{(30)}(3)}{30!}(x-3)^{30}
[/tex]

only because I thought that it would be the 30th derivative of f(3) not f^30 (3)
 
  • #10
I got that from the definition of the Taylor polynomial.
 
  • #11
okay. thanks so much again!
 

1. What is a Taylor Polynomial?

A Taylor Polynomial is a mathematical concept used to approximate a function using a finite number of terms. It is based on the Taylor Series, which represents a function as an infinite sum of derivatives at a specific point.

2. How do you evaluate a Taylor Polynomial?

To evaluate a Taylor Polynomial at a specific point, you need to plug in the value of that point in the polynomial. This will give you an approximation of the function's value at that point.

3. What does "f^30(3)" mean in the context of Taylor Polynomial homework?

In this context, "f^30(3)" means to evaluate the 30th derivative of the function f at the point x=3. This is a common notation used to represent the Taylor Polynomial and its derivatives.

4. Why is it important to evaluate a Taylor Polynomial at a specific point?

Evaluating a Taylor Polynomial at a specific point allows us to approximate the value of a function at that point. This can be useful in situations where the function is difficult to evaluate or when only a limited number of terms in the Taylor Polynomial are known.

5. Can a Taylor Polynomial be used to find the exact value of a function?

No, a Taylor Polynomial is an approximation of a function and cannot give the exact value. However, as the number of terms in the polynomial increases, the approximation becomes more accurate, and it can be used to get closer and closer to the actual value of a function.

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