- #1

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thus Maclaurin series

[tex] f(x) = f(0) + f'(0)x + \frac{f''(0)}{2} x^2 + \frac{f^{3}(0)}{6} x^3 [/tex]

[tex] f(x) = x + \frac{1}{2} x - \frac{1}{8} x^2 + \frac{3}{48} x^3 [/tex]

am i right so far?

To approximate f(0.5) i simply put x=0.5 in the above equation?

How do i fin the actual error, though?

DO i have to use the remainder in this? Please help!

Thank you