Show that Pn(x^2) is the 4n+2-nd Taylor polynomial of sin(x^2) by showing that(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \lim_{n\rightarrow infinity}[/tex] R2n+1(x^2) = 0.

note that Rn(x) represents the remainder

I'm stuck on this question, can anyone help me please?

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# Taylor Polynomials question

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