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Taylor Polynomials question

  1. Mar 13, 2005 #1
    Show that Pn(x^2) is the 4n+2-nd Taylor polynomial of sin(x^2) by showing that
    [tex] \lim_{n\rightarrow infinity}[/tex] R2n+1(x^2) = 0.

    note that Rn(x) represents the remainder

    I'm stuck on this question, can anyone help me please?
    Last edited: Mar 13, 2005
  2. jcsd
  3. Mar 13, 2005 #2


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    On what are you stuck? Do you know what Pn(x^2) is? Do you know what R2n+1(x^2) is? Do you know how to prove its limit goes to zero? Do you know why that limit would imply what you're trying to prove?
  4. Mar 13, 2005 #3
    I'm stuck on the entire question, I know what P and R are but i don't know how to prove the question. I also do not know why the limit of R helps solve this question.
    Last edited: Mar 13, 2005
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