I just want to check my answer. The question asks for the Taylor polynomial of degree 6 for ln(1-x^2) for -1<x<1 with c=0. I got tired after differentiating 6 times so I'm worried I made some mistakes along the way. The question also said: hint: evaluate the derivatives using the formula ln(1-x^2)=ln(1+x)+ln(1-x) So I differentiated ln(1+x)+ln(1-x) to get 1/(1+x) - 1/(1-x) for the first derivative and so on until the 6th derivative and I got: -2(x)^2/2! -12(x)^4/4! - 240(x^6)/6!