Calculating T2(x) at -1 with Error Less than 1/80 for f(x)=1/1-2x

  • Thread starter vickymath
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In summary, the conversation discusses finding the error in calculating T2(x) at -1 on the interval -1.5,-1 for the function f(x)=1/1-2x with an upper bound of 1/80. The speaker has calculated f"'=48/(1-2x)^4 and f"'(-1.5)=3/16 but is unsure of how to find the error at 1/80. They mention using the (n+1)th derivative at a point in the interval to find an upper bound on the error.
  • #1
vickymath
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i really need help with this prob f(x)=1/1-2x i have to calculate T2(x) at -1 on the interval -1.5,-1 with an error less than 1/80.
I got f"'=48/(1-2x)^4 and f"'(-1.5)=3/16 and i can't get the error at 1/80 . Thank you
 
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  • #2
There are several methods to give an upper bound on the error. The one I would use requires the (n+1)th derivative at some point in the interval - take the point where the absolute value of the derivative has the largest value for an upper bound.

Does this help to fill the gaps in your answer?
 
  • #3
yep, thank you
 

What is the problem asking me to do?

The problem is asking you to find the value of f(x) when x = 1/2.

How do I solve this problem?

To solve this problem, plug in 1/2 for x in the given function f(x)=1/1-2x and simplify the expression.

What is the value of f(x) when x = 1/2?

The value of f(x) when x = 1/2 is 1.

Can I use a calculator to solve this problem?

Yes, you can use a calculator to solve this problem. Simply input the expression 1/1-2(1/2) and the calculator will give you the answer of 1.

What happens if I plug in a different value for x?

The value of f(x) will change depending on the value of x. You can plug in different values for x to find the corresponding value of f(x).

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