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Taylor Series Help

  1. Dec 2, 2009 #1
    The Taylor Series of sin(x)=x-(x3/3!)+(x5/5!)-...

    What function of sin gives the following:

    ([tex]\pi[/tex]2/(22) - ([tex]\pi[/tex]4/(24*3!)+ ([tex]\pi[/tex]6/(26*5!) - ([tex]\pi[/tex]8/(28*7!)+...

    Please help me.
    Thank you.
     
  2. jcsd
  3. Dec 2, 2009 #2

    Mark44

    Staff: Mentor

    Your mix of [ tex] and [ SUP] tags makes it hard to tell what you wrote.
     
  4. Dec 2, 2009 #3

    Mark44

    Staff: Mentor

    If you factor out pi/2, what do you get?
     
  5. Dec 2, 2009 #4
    Thanks.
    Got that factored out.

    Is that my final answer?
     
  6. Dec 2, 2009 #5

    Mark44

    Staff: Mentor

    No, your final answer should be something like A*sin(B). Factoring out the pi/2 should give you an idea of what function your Maclaurin series represents.
     
  7. Dec 2, 2009 #6
    I dont recogize the series except that it comes from sin(something)...
     
  8. Dec 2, 2009 #7

    Mark44

    Staff: Mentor

    Isn't this what you have?
    [tex]\frac{\pi}{2}\left(\frac{\pi/2}{1!}~-~\frac{(\pi/2)^3}{3!}~+~\frac{(\pi/2)^5}{5!}~-~\frac{(\pi/2)^7}{7!}~...\right)[/tex]

    Looks pretty suggestive to me.
     
  9. Dec 2, 2009 #8
    I figured it out as soon as I posted my last reply.
    Thanks to you all!
     
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