I have got a question here that puzzles me.(adsbygoogle = window.adsbygoogle || []).push({});

How do I use TAYLOR SERIES to find the 2005th derivative for the function when x=0 for the following function:

f(x) = inverse tan [(1+x)/(1-x)]

Part (1) I was hinted that differentiating inverse tan x is = 1/(1+x^2).

Part (2) After which, I need to integrate 1/(1+x^2) and include some ARBITRARY constants to get back inverse tan [(1+x)/(1-x)]

I would like to know how whats the approach for part (2) as I am very confuse now.

Hope you can help. Thanks! :shy:

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# Taylor Series Problem

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