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Taylor series question.

  1. Nov 2, 2012 #1

    What polynomial should I use for finding Taylor series for 28^(3/5) up to the first order? I mean, aside x^3 around 2. Any suggestions?
  2. jcsd
  3. Nov 2, 2012 #2


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    Homework Helper
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    Use the Taylor series of f(x)=x^(3/5) around a=32 (=2^5).

  4. Nov 2, 2012 #3
    Did you not mean to write =2^3 (Instead of "=2^5")?
  5. Nov 2, 2012 #4
    I know that 32=2^5.
  6. Nov 2, 2012 #5


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    Staff Emeritus
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    Yes, and that is the fifth power of an integer that is closest to 28. That's the point.
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