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Taylor series

  1. Apr 18, 2010 #1
    1. The problem statement, all variables and given/known data

    find taylor series for [tex]\frac{x-1}{1+x}[/tex] at x=1

    2. Relevant equations

    3. The attempt at a solution

    how to change this form


    to something like this
    [tex]\frac{1}{1+a}[/tex] or [tex]\frac{1}{1-a}[/tex]

    help me please T_T

    or should i do like this


    and find fn(x) form?
  2. jcsd
  3. Apr 18, 2010 #2
    \frac{x-1}{1+x} = \frac{x+1-2}{x+1} = ... ?
  4. Apr 18, 2010 #3
    owhhhhhh, im soo stupid ngahahah, thank you thank you
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