Taylor series

[chenrim]

help with the following taylor series:

(y+dy)^0.5

Thanks

 

[BruceW]

I'm guessing that y is a constant and dy is your variable? and you are trying to expand around dy=0 ? well, you should try to use the definition of the Taylor series, and see what you get :)

 

[chenrim]

The thing is that i have an r.v (random variable) of the form Y=X^2

and by definition : fy(y)dy= P{y<Y<=y+dy}
i can substitute Y with (X)^2 and then i take the square root from both sides and get :
P{ sqrt(y)<X<= sqrt(y+dy) }}

now i want to show the PDF of X by the definition so i want to develop the right side of the inquality into a taylor series.
sqrt(y+dy) This is the term i want to develop into a taylor series . y and dy both are numbers. i tried to use Taylor's formula but couldn't get it right,

Hope you understand my question

thanks

 

[BruceW]

yes, I think I understand. you want to show how the pdf of X (from first principles) is related to the pdf of Y. Generally, you also need to take into account that X can be negative. (unless you want to specifically say that the random variable X cannot be negative). After this, I think it is easiest to use the cumulative distribution, and differentiate to get the probability density functions.

 

[chenrim]

Yes you right X also should be taken negative.
i didnt understand the step between line 2 and 3
https://drive.google.com/file/d/0B4wgc0vIE7CCUmpXLXJ0TEtIeUU/view?usp=sharing [Broken]

 

[Stephen Tashi]

i didnt understand the step between line 2 and 3
https://drive.google.com/file/d/0B4wgc0vIE7CCUmpXLXJ0TEtIeUU/view?usp=sharing [Broken]

It looks like an argument using differentials. If $f_X$ is the pdf of the random variable $X$ then the probability of the event $\{x: a < x \le a + h\} \approx f_X(a) h$. This is applied when $a = \sqrt{y}$ and $h = \frac{\triangle y} {2 \sqrt{y} }$ and again when $a = -\sqrt{y}$.