I have no idea how to do this :'( really the only part I don't understand is the ending part.....like for(adsbygoogle = window.adsbygoogle || []).push({});

the infinite sum of (1/n(n+1)).............I know you start of by partial fractions.....then you just plug in a few numbers for n.

so I end up with:

(1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ... + (1/n - 1/(n+1))

then in another problem...the infinite sum of ( 2/{(n-1)(n+1)} ) ends up like...

(1 - 1/3) + (1/2 - 1/4) +1/3 - 1/5) + ... + (1/(n-3) - 1/(n-1)) + (1/(n-2) - 1/n)

I want to know how you get the end results.....the ones with "n" in them....I don't understand how to get those numbers....or why they are what they are....

I understand the first part without the "n"....but I don't know how to end it with the "n"....I hope this makes since.

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# Telescoping Series

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