I have no idea how to do this :'( really the only part I don't understand is the ending part.....like for(adsbygoogle = window.adsbygoogle || []).push({});

the infinite sum of (1/n(n+1)).............I know you start of by partial fractions.....then you just plug in a few numbers for n.

so I end up with:

(1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ... + (1/n - 1/(n+1))

then in another problem...the infinite sum of ( 2/{(n-1)(n+1)} ) ends up like...

(1 - 1/3) + (1/2 - 1/4) +1/3 - 1/5) + ... + (1/(n-3) - 1/(n-1)) + (1/(n-2) - 1/n)

I want to know how you get the end results.....the ones with "n" in them....I don't understand how to get those numbers....or why they are what they are....

I understand the first part without the "n"....but I don't know how to end it with the "n"....I hope this makes since.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Telescoping Series

Loading...

Similar Threads for Telescoping Series | Date |
---|---|

I Help with simplifying series of hyperbolic integrals | Nov 19, 2017 |

I Taylor series | Jul 21, 2017 |

I How to understand Taylor/Mclaurin series? | May 19, 2017 |

I Divergence/Convergence for Telescoping series | Mar 25, 2017 |

Telescoping sum | Jan 2, 2015 |

**Physics Forums - The Fusion of Science and Community**