- #1
7C0A0A5
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I have no idea how to do this :'( really the only part I don't understand is the ending part...like for
the infinite sum of (1/n(n+1))....I know you start of by partial fractions...then you just plug in a few numbers for n.
so I end up with:
(1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ... + (1/n - 1/(n+1))
then in another problem...the infinite sum of ( 2/{(n-1)(n+1)} ) ends up like...
(1 - 1/3) + (1/2 - 1/4) +1/3 - 1/5) + ... + (1/(n-3) - 1/(n-1)) + (1/(n-2) - 1/n)
I want to know how you get the end results...the ones with "n" in them...I don't understand how to get those numbers...or why they are what they are...
I understand the first part without the "n"...but I don't know how to end it with the "n"...I hope this makes since.
the infinite sum of (1/n(n+1))....I know you start of by partial fractions...then you just plug in a few numbers for n.
so I end up with:
(1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ... + (1/n - 1/(n+1))
then in another problem...the infinite sum of ( 2/{(n-1)(n+1)} ) ends up like...
(1 - 1/3) + (1/2 - 1/4) +1/3 - 1/5) + ... + (1/(n-3) - 1/(n-1)) + (1/(n-2) - 1/n)
I want to know how you get the end results...the ones with "n" in them...I don't understand how to get those numbers...or why they are what they are...
I understand the first part without the "n"...but I don't know how to end it with the "n"...I hope this makes since.