(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A .20kg lead shot is heated to 90 degrees C and dropped into an ideal calorimeter containing .50kg of water initially at 20 degrees C. What is the final equilibrium temperance of the lead shot? Specific heat capacity of lead is 128 J/(kg*C), and water is 4186 J/(kg*C).

2. Relevant equations

Am I using the right formula, (c*m*delta T)_lead = (c*m*delta T)_water

What is the delta T of water in this equation?

3. The attempt at a solution

delta T_lead = (c*m*delta T)_water / (c*m)_lead

= [(4186)(.50)(?)] / [(128)(.20)]

= ?

**Physics Forums - The Fusion of Science and Community**

# Temp Equilibrium

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Temp Equilibrium

Loading...

**Physics Forums - The Fusion of Science and Community**