(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A piano is to be tuned at 20.0°C. However, when the temperature has lowered to 6.32°C, the piano will be off tune. By what percentage will the piano be off key at this low temperature?

2. Relevant equations

V = Square Root (3RT/M)

3. The attempt at a solution

T must be in Kelvins, so 20--> 293 K and 6.32--> 279.47 K

Because 3R/M is constant for both temperatures, you can ignore that in the equation so it is just the square root of temperature.

V1 = Sqrt (293)

V2 = Sqrt (279.47)

To find the percent difference, I did (1 - V2/V1) = 0.0234. Thus, the percent difference is 2.34%, but that wasn't the right answer.

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# Homework Help: Temperature and Frequency?

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