1. The problem statement, all variables and given/known data A piano is to be tuned at 20.0°C. However, when the temperature has lowered to 6.32°C, the piano will be off tune. By what percentage will the piano be off key at this low temperature? 2. Relevant equations V = Square Root (3RT/M) 3. The attempt at a solution T must be in Kelvins, so 20--> 293 K and 6.32--> 279.47 K Because 3R/M is constant for both temperatures, you can ignore that in the equation so it is just the square root of temperature. V1 = Sqrt (293) V2 = Sqrt (279.47) To find the percent difference, I did (1 - V2/V1) = 0.0234. Thus, the percent difference is 2.34%, but that wasn't the right answer.