I've been trying to solve this for about a week and I'm not sure where I'm going wrong. The problem is to figure out how much the temperature of the auditorium increases when its full of people. The room is 4350 cubic meters. The meeting lasts 30 minutes (1800 seconds) The specific heat capacity of air is 1.005 J/gram, or 1005 kJ/Kg The mass of air is 1.2 kg/m There are 823 people. Each person gives off about 100 watts per second. I've been using the equation Q = mc (delta T) To get Q, I do 823 * 100 * 1800, which is 148,140,000 So then I do 148,140,000 / 1.2kg/m (1005kJ/Kg) ( 4350), which is 148,140,000 / 5,246,100 = 28.238 degrees Celsius, which is way off. them.