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## Homework Statement

If 25g of water at a temperature of 10 degrees Celsius is mixed with 40 grams of water at 80 degrees Celsius what is the final temperature of the mixture?

## Homework Equations

Q

_{lost}+ Q

_{gained}= 0

Q=mcΔt

## The Attempt at a Solution

Attempt 2:

0.025(4186)(x-10) + (0.04)(4186)(x-40) = 0

x = 28.46

I don't know if I'm doing this right...