1. The problem statement, all variables and given/known data On a new Jekyll temperature scale, water freezes at 17 degree(s) J and boils at 97 degree(s) J. On another new temperature scale, the Hyde scale, water freezes at 0 degree(s) oH and boils at 120 degree(s) oH. If methyl alcohol boils at 84 oH, what is its boiling point on the Jekyll scale? 2. Relevant equations Jekyll has a FP 17 degrees higher than the Hyde scale. 3. The attempt at a solution Alright. Freezing point on Jekyll is 17 degrees higher than it is on Hyde. Therefore, any formula relating J and H must have the general form of: J(H) = H + 17, where H = 0. The general formula is: J(H) = H[(97-17)/120] + 17 Checking my work: H = 0, J = 17. Correct. H = 120. J = 97. Correct. What are some good ways of tackling this problem? Why does subtracting two points on the Jekyll scale divided by subtracting the two points on the Hyde scale multiplied by H work?