On a new Jekyll temperature scale, water freezes at 17 degree(s) J and boils at 97 degree(s) J. On another new temperature scale, the Hyde scale, water freezes at 0 degree(s) oH and boils at 120 degree(s) oH. If methyl alcohol boils at 84 oH, what is its boiling point on the Jekyll scale?
Jekyll has a FP 17 degrees higher than the Hyde scale.
The Attempt at a Solution
Alright. Freezing point on Jekyll is 17 degrees higher than it is on Hyde.
Therefore, any formula relating J and H must have the general form of:
J(H) = H + 17, where H = 0.
The general formula is:
J(H) = H[(97-17)/120] + 17
Checking my work:
H = 0, J = 17. Correct.
H = 120. J = 97. Correct.
What are some good ways of tackling this problem? Why does subtracting two points on the Jekyll scale divided by subtracting the two points on the Hyde scale multiplied by H work?