I see why, numerically speaking, deltaGo, defined as deltaGo = - RT ln K or deltaGo = deltaHo - TdeltaSo would be temperature dependent. But why is deltaGo temperature dependent, when it is simply Gibbs Free Energy at Standard State? Is this essentially saying that the definition of standard state differs per temperature given? As in deltaGo=A for the "standard" state of 298K and 1 bar, but deltaGo=B for the "standard" state of 312K and 1 bar? Thank you.