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Temperature - Pressure

  1. Mar 3, 2010 #1
    1. The problem statement, all variables and given/known data

    A cylinder of nitrogen is pressurised to 200 BAR at 25oC
    The cylinder is left to cool outside on a winters day to –5oC

    What is the pressure of the Nitrogen once it has cooled?



    2. Relevant equations

    P1/T1=P2/T2 ?


    3. The attempt at a solution

    25+273 = 298 Kelvin. 273-5=268 Kelvin.

    200/298=0.6711409396

    0.6711409396 x 268 = 179 BAR ?

    Have i used the relevant equation? Going through some practice questions but cant find the solutions. doh.

    cheers
     
  2. jcsd
  3. Mar 3, 2010 #2

    mgb_phys

    User Avatar
    Science Advisor
    Homework Helper

    You would normally just do
    200 * 268/298 = 180Bar

    Yes you are correct.
     
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