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The formation of condensation on a cold glass of water will cause it to warm up faster than it would have otherwise. If 4.5 gm of water condenses on a 122 gm glass containing 222 gm of water at 5.0 deg C, what will the final temperature be? Ignore the effect of the surroundings.

The answer for this is 14.9 deg C

But...I can't figure out how to get that answer. lol

Here is what I am doing, where do I go wrong?

(1 cal/g deg C)(222g)(Tf-5 degC) + (.2 cal/g deg C)(122g) (Tf-5 deg C)

(122cal/ deg C)(Tf-5 deg C) + (24.4 cal/deg C)(Tf-5 deg C)

(540 cal/g)=(146.4 cal/ deg C)(Tf-5 deg C)

/146.4 cal/ deg C

3.7=(Tf-5 deg C)

8.7=Tf

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# Temperature problem

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