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Temperature Rise?

  1. Apr 25, 2014 #1
    1. The problem statement, all variables and given/known data

    If a steel ball of mass 100 grams at a temperature of 100° is dropped into 1 litre of water at 20°C, what is the temperature rise? What would happen if it were dropped into a mixture of ice and water at 0°C?

    2. Relevant equations

    I assume that I'm required to use ΔQ = mcΔT. Also the general idea that heat lost by test sample = heat gained by water.

    3. The attempt at a solution

    At first I assumed:

    0.1 x C x (100-t1) = 1 x 4200 x (t2-20)

    But I don't think I can approach that due to a lack of knowledge on the change in temperature:

    Then I assumed if I was supposed to use (100-20) for both temperatures. Which ends up in C = 42000. But even then I'm not sure where to go. Is it possible that there isn't enough information given? Or am I encourage to find the specific heat capacity of steel from another source?

    Any help would be appreciated.
  2. jcsd
  3. Apr 25, 2014 #2

    Doc Al

    User Avatar

    Staff: Mentor

    What is the same is the final temperature of the steel and the water. And, yes, you need to look up the specific heat of steel. (Check your book.)
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