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Tennis Ball Collison

  1. Apr 8, 2016 #1
    1. The problem statement, all variables and given/known data
    A 0.060 kg tennis ball, moving with a speed of 2.50 m/s has a head on collision with a 0.090 kg ball initially moving toward it with a speed of 1.00 m/s. Assuming a perfectly elastic collision, what is the speed and direction of each ball after the collision?

    2. Relevant equations
    m1v1 + m2v2 = m1v1' +m2v2'

    v1-v2 = v2' - v1'

    3. The attempt at a solution

    I drew my positive x-direction to the right. Thus, ball 1 is going to the right prior to the collision and ball 2 is going to the left prior to the collision.


    v1' = (m1v1 + m2v2 - m2v2') / m1

    v1' = (0.06(2.5)-0.09-0.09v2')/(0.06)
    v1' = (0.06 - 0.09v2')/0.06
    v1' = -1.5v2'

    v1-v2 = v2' - v1'
    2.5+1 = 2.5v2'
    v2' = 1.40
    1.40 m/s to the right

    v1' = v2' - v1 + v2
    v1' = 1.4 - 2.5 - 1
    v1' = -2.1
    2.10 m/s to the left

    Does this look correct?
     
  2. jcsd
  3. Apr 8, 2016 #2

    PeroK

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    You could check whether momentum is indeed conserved in your solution.
     
  4. Apr 8, 2016 #3
    Duh. Thanks. :)
     
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