A 0.5 kg tennis ball is dropped from rest at a height of 5.6 m onto a hard floor.
A flash photograph shows that the ball is compressed a maximum of 0.6 cm when it strikes the floor.
b) Assuming that the acceleration of the ball is constant during its contact with the floor, what force does the floor exert on the ball?
(This is a problem in one-dimensional kinematics with constant acceleration. What is the acceleration of the ball when it is in contact with the floor?)
f = N
In the first part of the problem, I got velovity, 10.48m/s. I am now looking for acceleration, a. I attempted to find a using:
a = (v^2 - u^2)/2s
v = final velocity, 10.48
u = initial velocity, 0
s = displacement, 5.6
The answer is a = 9.80 and multiplying by mass 0.006 (0.6cm converted to meters) to get 0.059 as F.
The Attempt at a Solution