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Tensile Forces

  1. Nov 9, 2008 #1
    1. The problem statement, all variables and given/known data

    A circular steel wire 1.91m long must stretch no more than 0.0024m when a tensile force of 450N is applied to each end of the wire.

    What minimum diameter is required for the wire?

    2. Relevant equations

    [tex]p=\frac{F}{\Delta A}[/tex]

    3. The attempt at a solution

    I can't seem to solve for this at all. I've tried applying a volume to this exercise:

    [tex]A=V/l[/tex], where l is the length, then [tex]dA=\sqrt{dV/l-Vdl/l^2}[/tex]...

    [tex]p=\frac{F}{\Delta A}=\frac{F}{\sqrt{dV/l-Vdl/l^2}}[/tex]. This didn't work, as far as I remember...
  2. jcsd
  3. Nov 9, 2008 #2


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    Homework Helper

    Perhaps you want to look at Young's Modulus for the wire?

  4. Nov 9, 2008 #3
  5. Nov 9, 2008 #4
    I solved and got 2.1mm...

    It's not correct.
  6. Nov 9, 2008 #5


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    Homework Helper

    It's not what I got either.

    Maybe re-check your numbers?
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