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## Homework Statement

A circular steel wire 1.91m long must stretch no more than 0.0024m when a tensile force of 450N is applied to each end of the wire.

What minimum diameter is required for the wire?

## Homework Equations

[tex]p=\frac{F}{\Delta A}[/tex]

## The Attempt at a Solution

I can't seem to solve for this at all. I've tried applying a volume to this exercise:

[tex]A=V/l[/tex], where l is the length, then [tex]dA=\sqrt{dV/l-Vdl/l^2}[/tex]...

[tex]p=\frac{F}{\Delta A}=\frac{F}{\sqrt{dV/l-Vdl/l^2}}[/tex]. This didn't work, as far as I remember...