- #1
Javaid
- 2
- 0
Hi,
I am new to the tensile testing and still learning and would really appreciate the answer to a problem that I have been having.
I performed a lap-shear test on two foils of copper bonded in single lap joint. The copper broke before the bond does giving me a force of say 500N. I want to calculate the tensile lap shear strength. As per my understanding it should be achieved by by dividing the breaking force, in Newtons (500N), by the shear area, in square millimetres. But which is the shear area? Is it the width of the foil/bond multiplied by the thickness of the bonded area or is it the width of the foil/bond multiplied by the length of the bond?
Also, can this test give me the shear strength of the bond? (As the answer to this question is based on the answer to the previous question, I will ask it afterwards but it is here in case someone is kind enough to solve this problem for me)
Thanks in advance :)
I am new to the tensile testing and still learning and would really appreciate the answer to a problem that I have been having.
I performed a lap-shear test on two foils of copper bonded in single lap joint. The copper broke before the bond does giving me a force of say 500N. I want to calculate the tensile lap shear strength. As per my understanding it should be achieved by by dividing the breaking force, in Newtons (500N), by the shear area, in square millimetres. But which is the shear area? Is it the width of the foil/bond multiplied by the thickness of the bonded area or is it the width of the foil/bond multiplied by the length of the bond?
Also, can this test give me the shear strength of the bond? (As the answer to this question is based on the answer to the previous question, I will ask it afterwards but it is here in case someone is kind enough to solve this problem for me)
Thanks in advance :)