# Tensile Lap-Shear Testing

Hi,
I am new to the tensile testing and still learning and would really appreciate the answer to a problem that I have been having.
I performed a lap-shear test on two foils of copper bonded in single lap joint. The copper broke before the bond does giving me a force of say 500N. I want to calculate the tensile lap shear strength. As per my understanding it should be achieved by by dividing the breaking force, in newtons (500N), by the shear area, in square millimetres. But which is the shear area? Is it the width of the foil/bond multiplied by the thickness of the bonded area or is it the width of the foil/bond multiplied by the length of the bond?
Also, can this test give me the shear strength of the bond? (As the answer to this question is based on the answer to the previous question, I will ask it afterwards but it is here in case someone is kind enough to solve this problem for me)

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Danger
Gold Member
Hi,
But which is the shear area?
Hi; welcome aboard.
While I can't help with the actual problem, I have to ask you about terminology. Regardless of what you're trying to test, I would consider the point at which the foil tears to be the "shear area". I'm not educated in the field, though, so I might be missing something.

By shear area (cross-sectional area in square millimetres), I meant the value that will be used to divide with the breaking force to calculate tensile lap shear strength.
The foil tears outside the bonded region and I am confused how to calculate the tensile lap shear strength which should be be achieved by dividing the breaking force, in newtons (500N), by the shear area, in square millimetres. Hence the question...

Danger
Gold Member
Okay. Good luck with it. I haven't a clue, but someone here will be able to help.

PhanthomJay