Tension And Electric Charge

Then, you need to find the x-component of the electrical force, which is Tsin4. This is also equal to Fx, so you can set them equal to each other: Tsin4 = Fx. Plugging in the value for T that you found, you get 0.098239. However, in the next step, you used Tx instead of Fx, which is incorrect. This leads to an incorrect value for q.In summary, the error in your calculations was using arcsin instead of sin and using Tx instead of Fx. The correct value for q should be 1.711e-6.
  • #1
verd
146
0
Hey,

I thought I did this correctly and my answer turned out incorrect. Here's the problem:

http://synthdriven.com/images/deletable/help.jpg"

This is what I did:

In order to use Coloumb's Law, I need r, the distance between the two charges.

[tex]\arcsin{4}=\frac{x}{0.24m}[/tex]
[tex]x=0.24\arcsin{4}=0.098m[/tex]
[tex]r=2x=0.196m[/tex]

So that's r.

Then I need to pick one side of this thing apart and break it down into x and y-components.

With the weight, I have three forces acting on this thing. The tension in the rope, the weight, and the electrical force repelling each sphere.

My goal is to find the x-component of the electrical force so I can then plug it into Coulomb's law and find the charge.

For the weight,
Wx=0
Wy=-mg=-0.98

For the tension,
Tx=-Tsin4
Ty=Tcos4

For the electrical force,
Fx=Tsin4
Fy=0

To find T, all I did was:

FyNET=Wy+Ty+Fy=Tcos4-mg
(net force of y-component)

T=mg/cos4
Right??

So for T, I get 0.098239

Plugging that into Tx, I get 0.006853And then it goes into Coulomb's law. Which I have reformatted this way:

[tex]F=\frac{kq^2}{r^2}[/tex]

...Because both charges are supposed to be equal... Moving that around, I get:
[tex]q=\sqrt{\frac{Fr^2}{k}}[/tex]

Plugging in values, I got 1.711e-7What did I do wrong?
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
verd said:
This is what I did:

In order to use Coloumb's Law, I need r, the distance between the two charges.

[tex]\arcsin{4}=\frac{x}{0.24m}[/tex]
[tex]x=0.24\arcsin{4}=0.098m[/tex]
[tex]r=2x=0.196m[/tex]

So that's r.
That first equation should have sin(4), not arcsin(4).
 
  • #3


Hi there,

First of all, it's great that you are trying to use Coulomb's Law to solve this problem. However, there are a few mistakes in your calculations that led to the incorrect answer.

1. In order to use Coulomb's Law, you need to find the distance between the two charges, not the angle. The equation you used to find r is incorrect. The correct equation is: r = 0.24m / sin(4°) = 5.99m. This is the distance between the two charges.

2. Your calculations for the y-components of the tension and electrical force are incorrect. For the tension, Ty should be Tsin4°, not Tcos4°. For the electrical force, Fy should be -Tsin4° (since the force is repelling the spheres). Therefore, your equation for T is also incorrect. The correct equation is: T = mg / sin4° = 14.47N.

3. The x-component of the electrical force is not equal to Tx. It should be -Fx = -Tsin4° = -0.98N.

4. Your equation for q is incorrect. The correct equation is: q = sqrt(Fx * r^2 / k) = 3.43e-7 C.

I hope this helps you understand where you went wrong in your calculations. Remember to always double check your equations and units to ensure accuracy. Keep up the good work!
 

1. What is tension?

Tension, also known as mechanical tension, is the force that is exerted by a stretched object or material. It is the opposite of compression, and is commonly measured in units of newtons (N) or pounds (lbs).

2. How is tension related to electric charge?

In the context of electricity, tension refers to the potential difference between two points in an electric field. This potential difference is caused by the accumulation of electric charge on either end of the field.

3. What is electric charge?

Electric charge is a fundamental property of matter, and it is responsible for the electromagnetic interactions between particles. It can be either positive or negative, and is measured in units of coulombs (C).

4. How is electric charge calculated?

Electric charge can be calculated by multiplying the amount of charge (measured in coulombs) by the electric potential (measured in volts). This relationship is represented by the equation Q = CV, where Q is charge, C is capacitance, and V is voltage.

5. What is the difference between static and dynamic electric charge?

Static electric charge is the buildup of electric charge on an object that is not in motion, while dynamic electric charge is the movement of electric charge through a conducting material. Static electric charge can be generated by friction, while dynamic electric charge is typically associated with electric currents.

Similar threads

Replies
17
Views
976
  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
2K
Replies
22
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
781
  • Introductory Physics Homework Help
Replies
5
Views
802
  • Introductory Physics Homework Help
Replies
2
Views
856
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
819
  • Introductory Physics Homework Help
Replies
2
Views
2K
Back
Top