A uniform, horizontal flagpole of length 5.00 m and with a weight of 195 N(adsbygoogle = window.adsbygoogle || []).push({});

is hinged to a vertical wall at one end. A stuntwoman weighing 600 N hangs

from its other end. The flagpole is supported by a guy wire running from

its outer end to a point on the wall directly above the pole.

a) If the tension in this wire is not to exceed a force of 1070 N, what is

the minimum height above the pole at which it may be fastened to the wall?

b) If the flagpole remains horizontal, by how many newtons would the

tension be increased if the wire were fastened a distance 0.520 m below

this point?

** The moments about the point of hinging of the downward weights (that of the weight of the pole, and that of the stunt woman) must be balanced off by the upward moments at the end of the pole.

Hence how do you calculate the theoretical perpendicular force exerted at the end of the pole to maintain equilibrum?

Now, this theoretical upward force is the vertical component of the tension in the guy wire.

Given that the tension may not exceed 1070, what is the minimum angle with the pole the wire can be?

I calculated the downward forces = 195 N + 600 N = 795 N

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# Homework Help: Tension and height of flagpole

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