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Tension and Static Friction

  1. May 12, 2010 #1
    1. The problem statement, all variables and given/known data
    There is a 40 newton beam being held by a rope. The rope is attached at the top of the beam and the ground making a 25 degree angle at the top of the beam. There is a force applied to the beam with 200 newtons in the positive x direction. Find the tension and static friction.

    All I think I have figured out is:

    Ftoty = T(cos 25) - 200

    T = 200
    cos 25

    T = 220.676N


    Ftotx = 200N - Fs - Tsin 25

    Fs = 200N - (220.676 sin 25)

    Fs = 106.738

    Not sure if this is correct.
     
    Last edited: May 12, 2010
  2. jcsd
  3. May 12, 2010 #2
  4. May 12, 2010 #3
    [​IMG]

    No it's like this.
     
  5. May 12, 2010 #4

    PhanthomJay

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    Where is the 200 N force applied? Halfway up the vertical member??
     
  6. May 12, 2010 #5
    It does not state where it's applied. I'm guessing center of gravity?
     
  7. May 12, 2010 #6

    PhanthomJay

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    The 200 N force is apparently an applied horizontal force....have you stated the problem correctly? Does the vertical member only weigh 40 N? Something is not right....
     
  8. May 12, 2010 #7
    Yes this is how it is stated. The applied force states it is in the positive x direction (horizontal). I just can't figure out how to set up the problem.
     
  9. May 13, 2010 #8

    PhanthomJay

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    I guess you'll have to assume that the 200 N force is applied at the center of the vertical member, but the problem should have stated such. You should first find horizontal and vertical reactions at the ground on the vertical member and on the rope. Without taking a shortcut approach, try summing moments about the bottom of the rope = 0, to solve for the vertical reaction forces. The horizontal component of the reaction on the rope is trig related to the vertical component on the rope (Tx/Ty= tan 25).
     
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