A man of mass 60.8 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 17.2 kg and is 2.7 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope?
Torque = F r sin(angle to horizontal)
F = m g
The Attempt at a Solution
clockwise torque = anticlockwise torque
(2.7)(17.2) + (60.8)(9.8)(1.8) = F (2.7)
F = 414.4 N
I even tried it without useing the mass of the board and then placing the force caused by the mass (Fg) at the center, but all these thing didn't work.
We are also asked for the tension in the left rope after the tension in the right rope. But I cant figure out the right one first. Thanks in advance...