A load on which the force of gravity is 46 N hands from the centre of a frictionless clothesline, pulling its centre down so that each half of the line makes an angle of 25° with the horizontal. What is the force of tension in the line?
[tex]\Sigma[/tex]Y = FT - FG
= 2FTsin25° - FG
The Attempt at a Solution
I found that FT is equal to 46 N / 2sin25° [tex]\approx[/tex] 54 N. However, I don't understand if this is the force of tension in each half of the line, or through the whole line. Can someone help me understand this?