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Tension in 2 strings

  1. Sep 19, 2009 #1
    1. The problem statement, all variables and given/known data

    A 100-N body is shown suspended from a system of cords.

    http://bcs.whfreeman.com/WebPub/Physics/tiplerphysics6e_bridge/question_bank_images/4-50A.png?2417

    1. What is the tension (T2) in the tilted cord? Round your answer to three significant figures.

    2. What is the tension (T3) in the horizontal cord? Round your answer to three significant figures.

    2. Relevant equations

    F=ma

    3. The attempt at a solution

    I can't figure out how to solve the T3 part, I mean I have never dealt with a 90 degree string question.
     
  2. jcsd
  3. Sep 19, 2009 #2

    Doc Al

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    Staff: Mentor

    Consider the place where the cords meet. What forces act there? Hint: Consider horizontal and vertical components.
     
  4. Sep 19, 2009 #3

    rock.freak667

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    Draw the direction of the tension of T2.

    Split T2 into vertical and horizontal components. (T3 is purely horizontal)

    Now use equilibrium conditions

    ∑Fx=0 and ∑Fy=0
     
  5. Sep 19, 2009 #4
    I know that I have to split into x and y-components but I don't know how to split up T3 because it's at 90 degree angle. What will be it's x and y-component???
     
  6. Sep 20, 2009 #5

    rock.freak667

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    you don't need to split T3 into components. T3 is already in the x direction.
     
  7. Sep 20, 2009 #6
    So how do I proceed after finding x and y components of T2 and T3? I mean how will the equation be? I am totally confused.
     
  8. Sep 20, 2009 #7

    rl.bhat

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    y component of T2 = mg
    x component of T2 = T3.
     
  9. Sep 20, 2009 #8
    I still don't get it :(
     
  10. Sep 20, 2009 #9

    rl.bhat

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    Show your calculations.
     
  11. Sep 20, 2009 #10

    rock.freak667

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    Last edited by a moderator: Apr 24, 2017
  12. Sep 20, 2009 #11
    Ok I got the answer, is it T2=141N and T1=100N?
     
  13. Sep 20, 2009 #12

    rock.freak667

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    that should be correct (I don't know how many decimal places you wanted the answer to)
     
  14. Sep 20, 2009 #13
    Ah, finally thank you people! Thanks a lot.
     
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