# Tension in a 2 Mass System

1. Nov 14, 2007

### ibriggs

1. The problem statement, all variables and given/known data

In the ideal setup showin in the following figure, M1=3.0 kg and M2=2.5KG
A) What is the acceleration of the 2 mass system?
B) What is the tension in the string?

2. Relevant equations
Asys=M2 * g - M1 * g (sin$$\oslash$$) / M1 + M2

3. The attempt at a solution

Calculated the acceleration of the system using above equation and obtained:

Asys=1.24 m/s^2

My teacher gave me full credit on that part of my answer. On part B, however, I was expected to find the tension on the string. Here's what I attempted:
Asys=M1(g) -T / M1
1.24 m/s^2 = 2.5(9.8) - T / 5.5 kg

I am thinking I need to also divide by mass 2? Either way, I think I could use a fresh approach at thinking about tension. To me, it just seems like the transferred force through a string....I guess I'm a bit confused.

Ian

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Last edited: Nov 14, 2007
2. Nov 14, 2007

### rl.bhat

Asys=M1(g) -T / M1
1.24 m/s^2 = 2.5(9.8) - T / 5.5 kg

1.24 m/s^2 = [2.5(9.8) - T] / 2.5 kg Try this one and find T

3. Nov 14, 2007

### ibriggs

Wow, tell me my mistake wasn't that simple...

My new T= -0.127

Thanks guys...I can't even believe I didn't see that!