A 1.95 kg ball is attached to the bottom end of a length of 11.0 lb (48.9 N) fishing line. The top end of the fishing line is held stationary. The ball is released from rest while the line is taut and horizontal At what angle (measured from the vertical) will the fish line break? I've got the equation [tex] T = mg(3-2cos\theta)[/tex] but when I solve that for [tex] \theta[/tex] with T = 48.9, it says it's wrong. any thoughts?