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Tension in Circular Motion

  1. Oct 17, 2016 #1
    1. The problem statement, all variables and given/known data
    A hockey puck with mass 200 g is attached to a rope of length 62.0 cm and swung in a horizontal circle against the ice at a rate of 58.0 rpm. Assuming the ice is frictionless, what is the tension in the rope?

    2. Relevant equations
    FT = mω2r

    3. The attempt at a solution
    58rpm = 6.07 rad/s
    200g = 0.2 kg
    r = 0.31 m
    FT= (0.2)(6.07)2(0.31)
    = 2.28
    Is this not how you solve for tension in circular motion?
    I was given four answers which none of them match what I calculated 4.57 N, 417 N, 1.65×104 N, 1.09×103 N
     
  2. jcsd
  3. Oct 17, 2016 #2

    PhanthomJay

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    Yes but you used r = 0.31 m when it is given that the length of the rope is 0.62 m.. So what is the value of r?
     
  4. Oct 17, 2016 #3
    Oh so the radius isn't half the length of the rope?
    Edit: Ok I see why radius isn't half the length never mind and thank you for pointing that out
     
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