1. The problem statement, all variables and given/known data Two masses M1 = .600kg and M2 = 2.2kg connected by a cord of negligible mass and passes over a frictionless pulley of negligible mass. Assuming that y axis has a positive upward direction, what is the tension in the cord? 2. Relevant equations F = ma W = mg 3. The attempt at a solution I first tried to add up the Fg for both masses under the assumption that the opposing force would be the tension. I then subtracted the larger Fg from the smaller Fg which was also wrong. I then came upon this and tried to follow the process discussed there. I tried to solve for a based on the posts discussed in the other thread but was lost on posts 9 and 10 (NEwayz, back to what I did). I found the equations of the two blocks to be T - m1g = m1a and m2g - T = m2a. this makes T = m1a + m1g = m2g - m2a. Plugging in the numbers gives 5.88N + .6a = 21.56N - 2.2a solving for a gives a = 5.6ms-2 Plugging this back into the T equation gives a T of 9.24N I then double the T because there is T working on both ends of the rope and get 18.48N. I turns out that this is an incorrect answer and I am now out of ideas. Please help.