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a thin uniform rod of length l and density d is rotating with angular velocityω about an axis passing through one of its ends and perpendicular to it.find the tension int the rod as a function of x.(x= dist from axis of rotation).area of cross section = a
attempt at solution:
consider a small of length dx at dist x from axis.
for equilibrium of rod T = T-dT + dmω^2 x
dT = dm ω^2 x
integrating
T(x) =(d * a* ω^2 (x^2 - l^2))/2
this is negative of answer.where am i wrong?
attempt at solution:
consider a small of length dx at dist x from axis.
for equilibrium of rod T = T-dT + dmω^2 x
dT = dm ω^2 x
integrating
T(x) =(d * a* ω^2 (x^2 - l^2))/2
this is negative of answer.where am i wrong?