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Tension in the string of a rotating, massive pulley
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[QUOTE="haruspex, post: 4718150, member: 334404"] Why? r_l had to find the final velocity, and that has been done. The tension can now be deduced by considering the acceleration of either the wheel or the mass. Of the two, I would have thought the mass a little simpler, which may be what paisiello2 is hinting at. Also, it is not necessary to consider time if the appropriate SUVAT equation is used. r_l, you need the one that relates acceleration, initial speed, final speed and distance. Or, completely equivalently, consider force, energy change and distance. It's the same as using the SUVAT equation, but multiplying everything by the mass. [/QUOTE]
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Tension in the string of a rotating, massive pulley
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