# Tension in2 wires

1. Mar 3, 2010

### juggalomike

1. The problem statement, all variables and given/known data

Two wires are tied to the 200 g sphere shown in figure. The sphere revolves in a horiIzontal circle at a constant speed of 6.80 m/s.

http://img684.imageshack.us/img684/6537/knightfigure0761.jpg [Broken]

2. Relevant equations
Ca=m*v^2/r
f=ma

3. The attempt at a solution
I was able to find the radius using triangles, and with that
I know the centrifical acceleration is .200*6.8^2/.866=10.679
But i have no idea where to go from here

Last edited by a moderator: May 4, 2017
2. Mar 3, 2010

### Delphi51

Use trig to find what tension provides a horizontal component of half the centripetal force m*v^2/r

3. Mar 3, 2010

### juggalomike

Does that meen the tension of the 2 strings will be equal? that is whats throwing me off

4. Mar 3, 2010

### Delphi51

Yes. The tensions must be equal because it is perfectly symmetrical.

5. Mar 4, 2010

### rl.bhat

What about the weight of the sphere? Will it not contribute to the tension.

6. Mar 4, 2010

### chudd88

I may be wrong, but I don't see how it's possible for the tensions to be equal. In addition to the radial acceleration, there is also the vertical weight of the sphere. So, the upper string will be supporting the weight of the sphere, but the bottom string won't.

Imagine the system is just starting to spin. The sphere will hang, making the upper string tight, but the lower string will be slack. As the system spins, the ball will be forced outward. If the lower string weren't there, the top string might almost reach a horizontal angle if the rotation is fast enough. But the bottom string will kick in and keep the sphere from rising above a certain point. No matter how fast it spins, the top string will never be slack, and the way I figure it, the top string will always have greater tension than the bottom string.

Is that incorrect?

7. Mar 4, 2010

### PhanthomJay

I think you may be correct, however, in order to find out, the OP will have to assume that they are not equal and sum forces in the x direction and y directions and use Newton's laws, and then be sure that ther lower rope does not stay slack. Juggalomike, what's the acceleration in the x direction, and in the y direction?

8. Mar 4, 2010

### juggalomike

i believe acceleration in the x direction is 10.679 and the y direction is M*G

9. Mar 4, 2010

### PhanthomJay

that's the net centripetal force, in Newtons
Is there any acceleration in the y direction? And you are confusing acceleration with force, which are related by Newton's 2nd law: F_net = ma.

10. Mar 7, 2010

### rl.bhat

Let T1 and T2 are the tensions in upper and lower strings. Let 2θ be the angle between two strings. Then
T1*cosθ + T2*cosθ = m*v^2/R........(1)
T1*sinθ = T2*sinθ + mg........(2)
Solve these two equations to find T1 and T2.