Suppose the pulley is suspended by a cord C
Determine the tension in this cord after the masses are released and before one hits the ground. Ignore the mass of the pulley and cords.
Mass 1 : 1.2kg
Mass 2 : 3.2kg
Pulley and String mass is negligible
T-m1g = -m1a
T-m2g = m2a
Tension of pulley = T(C) -mg - 2T = ma(?)
The Attempt at a Solution
So I solved for the tensions in both ropes. Since they're equal I got T=17N
For acceleraton I got 4.4545455m/s. I'm just not too sure on the equation on the Tension of Cord C. Would it be the equation I mentioned above? When I use that I get an answer around 96. Is that right?