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Tension of Suspended Cable

  1. Mar 23, 2016 #1
    1. The problem statement, all variables and given/known data
    A 50.0 kg 6.00m awning is held up by a wire in the middle. A 15kg sign hangs at the end. Calculate the tension in the massless wire and the magnitude of the net force from the wall acting on the awning.
    The cable forms a 40 degree angle with the awning at the bottom right corner.
    2. Relevant equations
    Sum or Torque

    3. The attempt at a solution
    Sum of Torque=0=(mg)(L)+(Mg)(L/2)-(T)(L/2)Sin40)
    L's cancel
    (mg)+(Mg/2)=Tsin40/2
    (mg)+(Mg)/sin40=T
    ((15*9.81)+(50*9.81)/sin40)=T
    T=992N
    ???
    I'm not sure what the question means by net force from the wall. Is it just the normal force of the wall or do I have to use the tension to find it?
     
  2. jcsd
  3. Mar 23, 2016 #2

    TSny

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    Careful with treating the 2's.
    What can you say about the net force on the system?
     
  4. Mar 23, 2016 #3
    The net force would have to be zero. Does this mean that they are equal?
     
  5. Mar 24, 2016 #4

    TSny

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    It means ∑Fx = 0 and ∑Fy = 0. The wall exerts a force on the awning that could have both and x and y components.
     
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