1. The problem statement, all variables and given/known data A 500 kg beam is free to pivot about its lower end and is supported by a horizontal cable at its upper end, as shown in the figure. (figure has angle 35 degrees between beam and the wall) Assuming the mass of the beam is uniformly distributed, what is the tension in the cable? 2. Relevant equations Torque = r * F 3. The attempt at a solution Using pivot point at the end of the beam, the torque is 0. weight acting down on the beam is mg*l/2*sin(35). L is not givin not sure where to go from there.