- #1

- 36

- 0

## Homework Statement

A 500 kg beam is free to pivot about its

lower end and is supported by a horizontal

cable at its upper end, as shown in the

figure. (figure has angle 35 degrees between beam and the wall)

Assuming the mass of the beam is

uniformly distributed, what is the tension in

the cable?

## Homework Equations

Torque = r * F

## The Attempt at a Solution

Using pivot point at the end of the beam, the torque is 0.

weight acting down on the beam is mg*l/2*sin(35). L is not givin not sure where to go from there.