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Tension on elevator rope

  1. Sep 27, 2007 #1
    An elevator and its load have a combined mass of 1500 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 11 m/s, is brought to rest with constant acceleration in a distance of 43 m.

    First I found the time it to to decelerate
    D=(V+Vo)/2 T
    gave me a value of .78seconds
    plugged it into V=Vo+at

    so the force is 1500Kg * (9.8+14.1) which is 35850
    thats wrong, thanks in advance
  2. jcsd
  3. Sep 27, 2007 #2

    Doc Al

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    Staff: Mentor

    Redo this calculation.
  4. Sep 27, 2007 #3
    thanks, stupid decimal.
  5. Sep 29, 2011 #4
    How did you figure out the time?
  6. Sep 30, 2011 #5

    Doc Al

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    Staff: Mentor

    Read the first post. (Distance = average speed X time)

    This thread is 4 years old.
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