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The distance between two telephone poles is 50.5 m. When a 1.40 kg bird lands on the telephone wire midway between the poles, the wire sags 0.203 m. How much tension does the bird produce in the wire?

This is what I did

I divided 50.5/2 = 25.25m (to get length of one leg)

The other leg is = .203 m

So, Length of Hypotenuse = 25.2508

Weight of the bird = (9.81 * 1.40) = 13.734 N

Now to solve the problem I did the following

(Weight of the bird/ the distance of the wire sagged) * the hypotenuse

To get the tension

so, the tension is = 1708.35 N

But this is not the right answer, so can anyone tell me what I am doing wrong?

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# Homework Help: Tension Problem

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