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Freeze
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Ok this is the problem
The distance between two telephone poles is 50.5 m. When a 1.40 kg bird lands on the telephone wire midway between the poles, the wire sags 0.203 m. How much tension does the bird produce in the wire?
This is what I did
I divided 50.5/2 = 25.25m (to get length of one leg)
The other leg is = .203 m
So, Length of Hypotenuse = 25.2508
Weight of the bird = (9.81 * 1.40) = 13.734 N
Now to solve the problem I did the following
(Weight of the bird/ the distance of the wire sagged) * the hypotenuse
To get the tension
so, the tension is = 1708.35 N
But this is not the right answer, so can anyone tell me what I am doing wrong?
The distance between two telephone poles is 50.5 m. When a 1.40 kg bird lands on the telephone wire midway between the poles, the wire sags 0.203 m. How much tension does the bird produce in the wire?
This is what I did
I divided 50.5/2 = 25.25m (to get length of one leg)
The other leg is = .203 m
So, Length of Hypotenuse = 25.2508
Weight of the bird = (9.81 * 1.40) = 13.734 N
Now to solve the problem I did the following
(Weight of the bird/ the distance of the wire sagged) * the hypotenuse
To get the tension
so, the tension is = 1708.35 N
But this is not the right answer, so can anyone tell me what I am doing wrong?