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Introductory Physics Homework Help
Tension Problems Given Two Weights
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[QUOTE="yandereni, post: 4969372, member: 537759"] [h2]Homework Statement [/h2] One 3.2kg paint bucket(B) is hanging by a massless cord from another 3.2kg paint bucket(A), also hanging by a massless cord. a.) if the buckets are at rest, what is the tension in each cord? b.) if the two buckets are pulled upward with an acceleration of 1.6m/s[SUP]2[/SUP] by the upper cord, calculate the tension in each cord. this is one of the problems I am confused with actually [h2]Homework Equations[/h2] all i can make out is : 1. finding the tension when at rest box[a] ==> FtensA = (a[SUB]grav[/SUB])(m[SUB]A[/SUB]) + Ftens B box[B] [/B]==> FtensB = (a[SUB]grav[/SUB])(m[SUB]B[/SUB]) 2. finding the tension force given the acceleration 1.6m/s[SUP]2[/SUP] box[a]==>FtensA = m[SUB]A[/SUB]a[SUB]A[/SUB] +FtensB box==>FtensB = m[SUB]B[/SUB]a[SUB]B[/SUB] [B][B][h2]The Attempt at a Solution[/h2][/B][/B] I tried to solve for the tension when at rest and this is how it turned out: FtensA = (9.8m/s[SUP]2[/SUP])(3.2kg) + FtensB = 31.6N + 31.6N = 63.2N FtensB = (9.8m/s[SUP]2[/SUP])(3.2kg) = 31.6N Then I tried to solve for the tension given the acceleration FtensA = (1.6m/s[SUP]2[/SUP])(3.2) + FtensB = 5.12N + 5.12N = 10.24N FtensB = (1.6m/s[SUP]2[/SUP])(3.2kg) = 10.24N I really think that I'm wrong in here because its really confusing...Thanks In Advance! :) [COLOR=#0000ff]<<Moderator note: Edited for formatting.>>[/COLOR] [/QUOTE]
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Tension Problems Given Two Weights
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