A 97 250kg train pulls two freight cars. The first car has a mass of 51 355 kg and the second has a mass of 18 400 kg. The whole train accelerates at .01750m/s^2. What is the tension in the coupling between the locomotive and the first car? A. I used Ft=ma and took (51355)(.1750)= 8987.1 N What is the tension in the coupling between the first and the second freight cars? a. I took (m1-m2)(.01750)=Ft so (51 355-18400)(.01750)= 576.7 N I don't know if that is how I was supposed to do it. also, I wanted to ask if the force of friction is the same on all inclined surfaces (going up), even if a person is trying to go up the hill instead of going down. If a person was going up a 7 degree slope and a force was needed to have constant velocity. Would I still use Ff=umgcosO to find the force of friction and then set it equal to the needed force?