1. The problem statement, all variables and given/known data A hungry bear weighing 720 N walks out on a beam in an attempt to retrieve a basket of food hanging at the end of the beam. The beam is uniform, weighs 200 N, and is 5.40 m long; the basket weighs 80.0 N. a) When the bear is at x = 1.00 m, find the tension in the wire and the components of the force exerted by the wall on the left end of the beam. N (tension) N ( Fx) N ( Fy) 3. The attempt at a solution Okay well I sort of understood this question and created a balanced torque equation. After doing this I got that: Tension = 345.66 Fx = 172.83 But I need help with finiding Fy Please. I only have like one more chance to answer the question on my homework so I want to make sure I can get the right answer. I know I have to write out some equation like maybe: Rsin(theta) = 720 + 200 + 80 - 345.66sin(60) Is this correct? And if its not, am I on the right track?