1. The problem statement, all variables and given/known data blocks A B AND C are connected as show. block A and B have the same mass "m" and the coefficient of kinetic friction between each block is uk. block C descends with constant velocity. use 30 degrees for the angle of the incline. given m, uk find a. tension in rope between blocks A AND B b. mass of block C c. if the rope connected to block A is cut, determine the accel of block C 3. The attempt at a solution http://i.imgur.com/KJsro.png FAx = T1 - uk*N1 = 0 FAy = N1 - mg = 0 FBx = T2 - T1 - uk*N2 = 0 FBy = N - mg*cos(30) = 0 FCy = mc*g - T2 = 0 a. N1 = mg -> T1 = uk*mg b. N2 = mg*cos(30) - > T2 = uk*mg + uk*mg*cos(30) mc*g - ( uk*mg + uk*mg*cos(30) ) = 0 mc = uk*m + uk*m*sqrt(3)/2 I think these are right(confirm pls) c is what confuses me but my attempt: FBx = T2 - uk*N2 - g*sin(30) = 0 FBy = N2 = mg*cos(30) FCy = mc*g - T2 = mc*a T2 = uk*mg*cos(30) + g*sin(30) a = (mc * g - T2) / mc * g (uk*m + uk*m*sqrt(3)/2 - uk*m*sqrt(3)/2 + 1/2 ) / uk*m + uk*m*sqrt(3)/2 (g should cancel out) is this all right? thanks for any help.